Question

1)4√2+√50-√182)√3×(2√3+√12)3)(√5-2)²4)(√3-√2)(√3+√2)

Answer 1

1) 4√2+√50-√18 = 4√2 + 5√2 -3√2=6√2
2) √3×(2√3+√12) = √3×(2√3+2√3) = 4√3 * √3 = 4 * 3 = 12
3) не знаю
4) (√3-√2)(√3+√2) = 3- 2 = 1

Answer 2

1) 4√2 + √50 - √18 First, simplify the square roots: 4√2 = 4*√2 = √(16*2) = √32 √50 = √(25*2) = 5√2 √18 = √(9*2) = 3√2

Now, substitute the simplified square roots back into the original expression: √32 + 5√2 - 3√2 Combine like terms: (√32 + 5√2) - 3√2 √32 + 2√2

2) √3 × (2√3 + √12) First, simplify the square root: √12 = √(4*3) = 2√3

Now, substitute the simplified square root back into the original expression: √3 × (2√3 + 2√3) Multiply: 2√3 + 2√3 Combine like terms: 4√3

3) (√5 - 2)² This is a binomial squared, which can be expanded using the formula (a - b)² = a² - 2ab + b²: (√5 - 2)² = (√5)² - 2(√5)(2) + 2² = 5 - 4√5 + 4 = 9 - 4√5

4) (√3 - √2)(√3 + √2) This is a difference of squares, which can be expanded using the formula (a - b)(a + b) = a² - b²: (√3)² - (√2)² = 3 - 2 = 1