Question

Тема Линейная функция и её график ! Помогите решить 4 задачи! (мне нужно решение на рисунках то есть нарисовать а не написать)1) Построить прямую , проходящую через точки A(0.5) , и B(-2.5) . Чему равны ординаты ; обциссы точек ,лежащие на прямой AB? 2) Построить прямую , проходящую через точки A(-2.3) и B(-2,-1) . Чему равны ординаты ; обциссы точек ,лежащие на прямой AB? 3) Даны точки A(5.4) B(2.-1) C(-3.2) D(-4.-4). Построить точки, симметричные им ; 1) относительно оси Ox; 2) Относительно точки (0;0) . Определить координаты полученных точек . 4) Даны точки A(2.-2) B(1.1) C(-3.2).D(-4.(-2 1/2- минус две целых одна вторая) Построить точки, симметричные им ; 1) относительно оси Ox; 2) Относительно точки (0;0) . Определить координаты полученных точек .

Answer 1

Ответ во вложении

Answer 2

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Answer 3

Linear Function and Its Graph

A linear function is a function that can be defined by a straight line when graphed. It has the general form y = mx + b, where m is the slope of the line and b is the y-intercept.

Task 1:

1) Plot a Line Passing Through Points A(0, 5) and B(-2, 5)

To find the equation of the line passing through points A(0, 5) and B(-2, 5), we can use the point-slope form of a linear equation: y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

The slope m can be calculated as (y2 - y1) / (x2 - x1). Substituting the values of A and B, we get: m = (5 - 5) / (0 - (-2)) = 0 / 2 = 0

So, the equation of the line passing through A and B is y = 5.

2) Ordinates and Abscissas of Points on Line AB

As the equation of the line is y = 5, the ordinate (y-coordinate) of any point on this line will be 5. The abscissa (x-coordinate) can be any real number.

Task 2:

1) Plot a Line Passing Through Points A(-2, 3) and B(-2, -1)

The line passing through points A(-2, 3) and B(-2, -1) is a vertical line. The equation of this line is x = -2.

2) Ordinates and Abscissas of Points on Line AB

As the equation of the line is x = -2, the abscissa (x-coordinate) of any point on this line will be -2. The ordinate (y-coordinate) can be any real number.

Task 3:

1) Plot Symmetric Points to A(5, 4), B(2, -1), C(-3, 2), and D(-4, -4)

To find the points symmetric to A, B, C, and D: 1) Symmetric to A(5, 4) with respect to the x-axis is A'(5, -4). 2) Symmetric to A(5, 4) with respect to the origin is A'(-5, -4). 3) Symmetric to B(2, -1) with respect to the x-axis is B(2, 1). 4) Symmetric to B(2, -1) with respect to the origin is B(-2, 1). 5) Symmetric to C(-3, 2) with respect to the x-axis is C(-3, -2). 6) Symmetric to C(-3, 2) with respect to the origin is C(3, -2). 7) Symmetric to D(-4, -4) with respect to the x-axis is D(-4, 4). 8) Symmetric to D(-4, -4) with respect to the origin is D(4, 4).

Task 4:

1) Plot Symmetric Points to A(2, -2), B(1, 1), C(-3, 2), and D(-4, -2.5)

1) Symmetric to A(2, -2) with respect to the x-axis is A'(2, 2). 2) Symmetric to A(2, -2) with respect to the origin is A'(-2, 2). 3) Symmetric to B(1, 1) with respect to the x-axis is B(1, -1). 4) Symmetric to B(1, 1) with respect to the origin is B(-1, -1). 5) Symmetric to C(-3, 2) with respect to the x-axis is C(-3, -2). 6) Symmetric to C(-3, 2) with respect to the origin is C(3, -2). 7) Symmetric to D(-4, -2.5) with respect to the x-axis is D(-4, 2.5). 8) Symmetric to D(-4, -2.5) with respect to the origin is D(4, 2.5).

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.