Question

Найдите корень уравнения log2(-3x+8)=7 у меня получилось 120 в ответе

Answer 1

$log_2(-3x+8)=7\\-3x+8=128\\3x=-120\\x=-40$

Answer 2

log₂(-3x+8)=7

-3x+8=2⁷

-3x+8= 128

-3х = 128 -8

-3х =120

х= 120: (-3)

х=-40

 

Answer 3

I can help you with your math problem. The equation you have is $$\log_2(-3x+8)=7$$ To find the root, you need to solve for x. First, you can rewrite the equation using the exponent rule of logarithms: $$-3x+8=2^7$$ Then, you can simplify the equation by subtracting 8 from both sides: $$-3x=2^7-8$$ Next, you can divide both sides by -3: $$x=\frac{2^7-8}{-3}$$ Finally, you can evaluate the expression using a calculator or by hand: $$x=-34.333...$$

Your answer of 120 is incorrect. You might have made a mistake in your calculations or in applying the logarithm rules. You can check your work by plugging in the value of x into the original equation and see if it is true. I hope this helps you understand how to solve logarithmic equations.Ответь+подробно.+Найдите+корень+уравнения+log2(-3x+8)=7+у+меня+получилось+120+в+ответе