Question

одна швея сшила фартуки за 3 дня, другая за 7 дней. Вместе они сшили 135 фартуков. Сколько фартуков сшила одна швея в день, если известно, что вторая швея ежедневно шила на 5 фартуков меньше, чем первая

Answer 1

X*3+(x-5)*7=135
3x+7x-35=135
X=17 сшила 1 швея за 1 день
17-5=2 шила 2 швея за 1 день

Answer 2

Problem Analysis

We are given that one seamstress sewed aprons in 3 days, while another seamstress sewed aprons in 7 days. Together, they sewed a total of 135 aprons. We need to determine how many aprons one seamstress sewed per day, given that the second seamstress sewed 5 aprons less than the first seamstress each day.

Solution

Let's denote the number of aprons sewn by the first seamstress per day as x. Since the second seamstress sewed 5 aprons less than the first seamstress each day, the number of aprons sewn by the second seamstress per day can be represented as x - 5.

We know that the first seamstress sewed aprons in 3 days, so the total number of aprons sewn by the first seamstress is 3x. Similarly, the second seamstress sewed aprons in 7 days, so the total number of aprons sewn by the second seamstress is 7(x - 5).

According to the given information, the total number of aprons sewn by both seamstresses is 135. Therefore, we can write the equation:

3x + 7(x - 5) = 135

Simplifying the equation:

3x + 7x - 35 = 135

10x = 170

x = 17

Therefore, one seamstress sewed 17 aprons per day.

Answer

One seamstress sewed 17 aprons per day.

Explanation

Let's verify our answer using the given information. If one seamstress sewed 17 aprons per day, then in 3 days, she would have sewn 3 * 17 = 51 aprons. Similarly, if the second seamstress sewed 5 aprons less per day, she would have sewn 17 - 5 = 12 aprons per day. In 7 days, she would have sewn 7 * 12 = 84 aprons. The total number of aprons sewn by both seamstresses is 51 + 84 = 135, which matches the given information. Therefore, our answer is correct.