Question

В окружности с центром О отрезки АС и ВD - диаметры. угол АОD 50 градусов . гайдите угол АСВ. ответ дайте в градусах

Answer 1

Надо по рисунку.
угол АОВ=50=углуВОС как вертикальные=50
ВО и ОС - радиусы, значит ВО=ОС и треугольник ВОС - равнобедренный, угол СОВ=углуОВС=(180-50)/2=65

Answer 2

Problem Analysis

We are given a circle with center O, where AC and BD are diameters. The angle AOD is 50 degrees. We need to find the angle ACB.

Solution

To find the angle ACB, we can use the fact that angles inscribed in the same arc are equal. Since AC and BD are diameters, they intersect at point O, and angle AOD is 50 degrees, we can conclude that angle ACB is also 50 degrees.

Therefore, the angle ACB is 50 degrees.

Conclusion

The angle ACB is 50 degrees.