Question

Х^2+2x-8=0 помогите)

Answer 1

$x_{1,2}= \frac{-2+- \sqrt{4+4*8} }{2}= \frac{-2+-6}{2} \\ x_1=2 \\ x_2=-4$

Answer 2

Solving the Quadratic Equation x^2 + 2x - 8 = 0

To solve the quadratic equation x^2 + 2x - 8 = 0, we can use the quadratic formula or factorization method.

Using the Quadratic Formula

The quadratic formula states that for the quadratic equation ax^2 + bx + c = 0, the solutions for x are given by: x = (-b ± √(b^2 - 4ac)) / (2a)

For the equation x^2 + 2x - 8 = 0: - a = 1 - b = 2 - c = -8

Substitute these values into the quadratic formula to find the solutions for x: x = (-2 ± √(2^2 - 4*1*(-8))) / (2*1)

Calculating the discriminant and the solutions: D = b^2 - 4ac = 2^2 - 4*1*(-8) = 4 + 32 = 36 x1 = (-b + √D) / (2a) = ( -2 + √36 ) / 2 = ( -2 + 6 ) / 2 = 4 / 2 = 2 x2 = (-b - √D) / (2a) = ( -2 - √36 ) / 2 = ( -2 - 6 ) / 2 = -8 / 2 = -4

So, the solutions for the equation x^2 + 2x - 8 = 0 are x = 2 and x = -4.

Using Factorization Method

We can also solve the equation by factoring it: x^2 + 2x - 8 = 0 x^2 - 2x + 4x - 8 = 0 x(x - 2) + 4(x - 2) = 0 (x + 4)(x - 2) = 0

Setting each factor to zero gives us the solutions: x + 4 = 0 or x - 2 = 0 x = -4 or x = 2

So, the solutions for the equation x^2 + 2x - 8 = 0 are x = 2 and x = -4.

Therefore, the solutions to the equation x^2 + 2x - 8 = 0 are x = 2 and x = -4.