Question

Решите систему уравнений:

Answer 1

{У=10-3х ; 2(10-3х)^2+х(10-3х)-3х-6(10-3х)=2(100-60х+9х^2)+10х-3х^2-3х-60+18х= считаешь и в итоге получаешь квадратное уравнение (через дискременант) потом пишешь две системы{ х1=.....;у =10-3*х1= и { х2=.......; у=10-3*х2= все (х1 и х2 это корни получив. Дискременанта)

Answer 2

System of Equations

The given system of equations is: - Equation 1: 2x - y = 7 - Equation 2: x^2 - xy = 12

To solve this system of equations, we can use various methods such as substitution, elimination, or graphing. Let's solve it using the substitution method.

Substitution Method

Step 1: Solve one equation for one variable in terms of the other variable. Let's solve Equation 1 for x: 2x - y = 7 2x = y + 7 x = (y + 7)/2

Step 2: Substitute the expression for x in terms of y into the other equation. Substituting x = (y + 7)/2 into Equation 2: ((y + 7)/2)^2 - ((y + 7)/2)y = 12

Simplifying the equation: (y^2 + 14y + 49)/4 - (y^2 + 7y)/2 = 12 (y^2 + 14y + 49 - 2y^2 - 14y)/4 = 12 (y^2 - 2y^2 + 14y - 14y + 49)/4 = 12 (-y^2 + 49)/4 = 12 -y^2 + 49 = 48 -y^2 = -1 y^2 = 1 y = ±1

Step 3: Substitute the values of y back into the expression for x to find the corresponding values of x. For y = 1: x = (1 + 7)/2 x = 8/2 x = 4

For y = -1: x = (-1 + 7)/2 x = 6/2 x = 3

Therefore, the solutions to the system of equations are: (x, y) = (4, 1) and (x, y) = (3, -1).

Note: The solutions to the system of equations are (4, 1) and (3, -1).

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