Question

Решить уравнение: 4х^2 -(2х-1)^2=15^ - степеньПомогите Пожалуйста!!!Алгебра 7 класс

Answer 1

4x^2-(4x^2-4x+1)=15
4x^2-4x^2+4x-1=15
4x-1=15
4x=15+1
4x=16
x=16:4
x=4

Answer 2

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Answer 3

Solving the Equation

To solve the equation 4x^2 - (2x-1)^2 = 15, we can start by expanding and simplifying the equation.

First, let's expand the squared term (2x-1)^2: Expand: (2x-1)^2 = (2x-1)(2x-1) = 4x^2 - 2x - 2x + 1 = 4x^2 - 4x + 1

Now, we can substitute this expansion back into the original equation: Substitute: 4x^2 - (4x^2 - 4x + 1) = 15

Simplify the equation by combining like terms: Simplify: 4x^2 - 4x^2 + 4x - 1 = 15 4x - 1 = 15

Next, isolate the variable x by adding 1 to both sides of the equation: Isolate x: 4x = 15 + 1 4x = 16

Finally, solve for x by dividing both sides by 4: Solve for x: x = 16 / 4 x = 4

Answer

So, the solution to the equation 4x^2 - (2x-1)^2 = 15 is x = 4.