Question

Решите уравнения: а) 2x+5-2(x+1)+11 б) 5(2y-4)=2(5y-10) в) 3y-(y-19)=2y г) 6x=1-(4-6x)

Answer 1

А где стоит знак = в уравнении а)?

Answer 2

Решение уравнений:

а) 2x + 5 - 2(x + 1) = 11

To solve this equation, we'll use the distributive property to simplify the expression: \[ 2x + 5 - 2x - 2 = 11 \] \[ 2x - 2x + 5 - 2 = 11 \] \[ 5 - 2 = 11 \] \[ 3 = 11 \]

The equation 3 = 11 is not true, so this equation has no solution.

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б) 5(2y - 4) = 2(5y - 10)

To solve this equation, we'll start by distributing the multiplication on both sides of the equation: \[ 10y - 20 = 10y - 20 \]

The equation 10y - 20 = 10y - 20 is an identity, which means it is true for all values of y. Therefore, the solution to this equation is all real numbers.

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в) 3y - (y - 19) = 2y

To solve this equation, we'll simplify the expression by distributing the negative sign: \[ 3y - y + 19 = 2y \] \[ 2y + 19 = 2y \]

Subtracting 2y from both sides of the equation, we get: \[ 19 = 0 \]

The equation 19 = 0 is not true, so this equation has no solution.

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г) 6x = 1 - (4 - 6x)

To solve this equation, we'll start by simplifying the expression inside the parentheses: \[ 6x = 1 - 4 + 6x \] \[ 6x = -3 + 6x \]

Subtracting 6x from both sides of the equation, we get: \[ 0 = -3 \]

The equation 0 = -3 is not true, so this equation has no solution.

In summary, the solutions to the given equations are as follows: - Equation (a) has no solution. - Equation (б) has all real numbers as its solution. - Equation (в) has no solution. - Equation (г) has no solution.