Question

A=30,6, a (1)=12,2 ,d=0,4 Найти: n-?

Answer 1

Составляем уравнение: 12,2+(n-1)*0,4=30,6        (n-1)*0,4=18,4      n-1=46   
n=47   

Answer 2

This is a question about arithmetic progression. To find the value of n, we need to use the formula:

$$a_n = a_1 + (n-1)d$$

where $a_n$ is the nth term, $a_1$ is the first term, $d$ is the common difference, and $n$ is the number of terms.

We are given that $A = 30.6$, $a_1 = 12.2$, and $d = 0.4$. We can substitute these values into the formula and solve for $n$:

$$30.6 = 12.2 + (n-1)0.4$$

$$18.4 = (n-1)0.4$$

$$46 = n-1$$

$$n = 47$$

Therefore, the value of n is 47. This means that the 47th term of the arithmetic progression is 30.6.

If you need more help with arithmetic progression, you can use some online calculators or resources, such as [Web 2.0 scientific calculator](https://web2.0calc.com/), [Step-by-Step Calculator - Symbolab](https://www.symbolab.com/solver/conversion-fraction-to-decimal-calculator), or [4.2 Linear Approximations and Differentials - OpenStax](https://openstax.org/books/calculus-volume-1/pages/4-2-linear-approximations-and-differentials). I hope this answer was helpful.