Question

(3-b)(b^2+3b+9) помогите))... не могу понять как выйдет 27-b^3

Answer 1

так это по формуле например а^3-b^3=(a-b)(a^2+ab+b^2)

Answer 2

I can help you with math problems. To solve this problem, you need to multiply the two brackets and then simplify the result. Here are the steps:

- Step 1: Multiply the first term of the first bracket by the second bracket: $(3-b)(b^2+3b+9) = 3(b^2+3b+9) - b(b^2+3b+9)$ - Step 2: Distribute the 3 and the -b over the second bracket: $3(b^2+3b+9) - b(b^2+3b+9) = 3b^2 + 9b + 27 - b^3 - 3b^2 - 9b$ - Step 3: Combine like terms and simplify: $3b^2 + 9b + 27 - b^3 - 3b^2 - 9b = -b^3 + 27$

Therefore, the final answer is $-b^3 + 27$. I hope this helps you understand how to solve this problem.Ответь+подробно.+(3-b)(b^2+3b+9)+помогите))...+не+могу+понять+как+выйдет+27-b^3