Question

Преобразуйте квадрат двухчлена в многочлен стандартного вида(6p в 5 степени+7)во 2 степени (4w в 3 степени -5f в 6 степени )ао второй степени (8p во 2 степени +2f в 4 степени)во 2 степени срочно дам 25 баллов

Answer 1

Решение задания смотри на фотографии

Answer 2

Converting the Square of a Binomial to Standard Form

To convert the square of a binomial to standard form, we need to expand the expression. Let's start with the first expression:

(6p + 5^7)^2

To expand this expression, we can use the formula for squaring a binomial, which is:

(a + b)^2 = a^2 + 2ab + b^2

In our case, a = 6p and b = 5^7. Let's substitute these values into the formula:

(6p + 5^7)^2 = (6p)^2 + 2(6p)(5^7) + (5^7)^2

Simplifying this expression, we get:

(6p + 5^7)^2 = 36p^2 + 2(6p)(5^7) + 5^14

Now, let's move on to the second expression:

(4w^3 - 5f^6)^2

Using the same formula, we have a = 4w^3 and b = -5f^6:

(4w^3 - 5f^6)^2 = (4w^3)^2 + 2(4w^3)(-5f^6) + (-5f^6)^2

Simplifying this expression, we get:

(4w^3 - 5f^6)^2 = 16w^6 - 40w^3f^6 + 25f^12

Finally, let's consider the third expression:

(8p^2 + 2f^4)^2

Using the formula, we have a = 8p^2 and b = 2f^4:

(8p^2 + 2f^4)^2 = (8p^2)^2 + 2(8p^2)(2f^4) + (2f^4)^2

Simplifying this expression, we get:

(8p^2 + 2f^4)^2 = 64p^4 + 32p^2f^4 + 4f^8

So, the expanded forms of the given expressions are:

1. (6p + 5^7)^2 = 36p^2 + 2(6p)(5^7) + 5^14 2. (4w^3 - 5f^6)^2 = 16w^6 - 40w^3f^6 + 25f^12 3. (8p^2 + 2f^4)^2 = 64p^4 + 32p^2f^4 + 4f^8

I hope this helps! Let me know if you have any further questions.