Question

6 * 7 ^ log7 ^2 , плиз

Answer 1

A^loga b=b 6*2=12 первое - это свойство логарифма

Answer 2

$6\cdot 7^{\log_72}=6\cdot 2=12$

Answer 3

6 * 7 ^ log7^2

First, let's solve the exponent inside the logarithm. log7^2 = log49

Next, we can rewrite log49 in exponential form. log49 = x, where 7^x = 49 7^x = 49 7^x = 7^2 x = 2

Now we can substitute the value of log7^2 back into the original expression. 6 * 7 ^ 2 6 * 49 294

So, the value of the expression 6 * 7 ^ log7^2 is 294.