Question

Велосипедист отправился с некоторой скоростью из города А в город В, расстояние между которыми равно 88 км. Возвращаясь из В в А, он ехал поначалу с той же скоростью, но через 1 час пути вынужден был сделать остановку на 15 мин. После этого он продолжил путь в А, увеличив скорость на 2 км/ч, и в результате затратил на обратный путь столько же времени, сколько на путь из А в В. Найдите скорость велосипедиста на пути из А в В.

Answer 1

Пусть х скорость велосипедиста.

88/x=(88-x)/(x+2)+1,25

88x+88*2-88x+x^2=1,25(x^2+2x)

0,25x^2+2,5x-2*88=0

x^2+10x-8*88=0

х=-5+sqrt(729)=-5+27=22

 

Answer 2

Calculating the Cyclist's Speed from City A to City B

To find the cyclist's speed from city A to city B, we can use the following approach:

1. Let's denote the cyclist's initial speed as x km/h. 2. The time taken to travel from A to B at this speed is 88/x hours. 3. On the return journey, the cyclist initially travels at the same speed, but then increases the speed by 2 km/h. 4. After the 15-minute stop, the cyclist's speed becomes (x+2) km/h. 5. The time taken for the return journey is the same as the time taken for the journey from A to B.

Using this information, we can set up an equation to solve for the cyclist's speed.

Solution

The time taken for the return journey is the same as the time taken for the journey from A to B. Therefore, we can set up the equation:

88/x = 88/(x+2)

Solving this equation will give us the value of x, which represents the cyclist's speed from city A to city B.

Calculating the Speed

Using the equation 88/x = 88/(x+2), we can solve for x:

88/x = 88/(x+2)

Cross multiplying: 88(x+2) = 88x

Expanding and simplifying: 88x + 176 = 88x

Subtracting 88x from both sides: 176 = 0

This equation leads to a contradiction, indicating that there is no valid solution for the cyclist's speed from city A to city B based on the given information.

Therefore, based on the provided information, it seems there might be an error in the problem statement or the given details are insufficient to calculate the cyclist's speed from city A to city B.