Question

Log3(x+1)+log3(x+3)=1

Answer 1

Так как это сумма, то пользуемся свойством
Log3 ((x+1)×(x+3))=1
Log3 (x^2+3x+x+3)= log3 (3)
Логарифм можем сократить
 X^2+4x+3=3
X^2+4x=0
X (x+4)
X1=0
X2=-4
Это ответ))

Answer 2

I can help you with math problems, among other things. To solve this equation, you need to use the properties of logarithms and then apply the quadratic formula. Here are the steps:

- Use the product rule of logarithms to combine the two terms on the left side: $$\log_3(x+1)+\log_3(x+3)=\log_3((x+1)(x+3))$$ - Rewrite the equation in exponential form: $$(x+1)(x+3)=3^1$$ - Expand the left side and subtract 3 from both sides: $$x^2+4x-6=0$$ - Use the quadratic formula to find the values of x: $$x=\frac{-4\pm\sqrt{16+24}}{2}$$ - Simplify the expression and get the final answer: $$x=-2\pm\sqrt{10}$$

I hope this helps you understand how to solve this problem. If you have any other questions, feel free to ask me.Ответь+подробно.+Log3(x+1)+log3(x+3)=1