Question

Решите систему уравнений методом алгебраического сложения x^2-y^2=-5,x^2+y^2=13 пожалуйста

Answer 1

Смотри фото)))))))))))))))

Answer 2

Solution to the System of Equations

To solve the system of equations using the method of algebraic addition, we have the following equations:

Equation 1: x^2 - y^2 = -5. Equation 2: x^2 + y^2 = 13.

To solve this system, we can add the two equations together to eliminate the y^2 term:

(x^2 - y^2) + (x^2 + y^2) = -5 + 13 2x^2 = 8 x^2 = 4 x = ±2

Now, we can substitute the value of x into either of the original equations to solve for y. Let's substitute x = 2 into Equation 2:

(2^2) + y^2 = 13 4 + y^2 = 13 y^2 = 9 y = ±3

Therefore, the solutions to the system of equations are: (x, y) = (2, 3), (2, -3), (-2, 3), (-2, -3).

Please let me know if you need any further assistance!