Question

1)соsx=22)соs=-1/2МНЕ ПРОСТО КОРНИ НАПИСАТЬ

Answer 1

1) cosx=2 

Это уравнение не имеет корней , так как | cosx|<=1

2) cosx=-1/2

Х=+-2 П/3 +2Пk , k принадлежит Z

Answer 2

Solution:

To find the roots of the given equations, let's solve them one by one.

Equation 1:

The equation is cos(x) = -1/2.

To find the values of x that satisfy this equation, we can refer to the trigonometric unit circle or use the inverse cosine function.

The unit circle shows that the cosine function is equal to -1/2 at two angles: 2π/3 and 4π/3.

Therefore, the solutions for cos(x) = -1/2 are:

- x = 2π/3 + 2πn, where n is an integer. - x = 4π/3 + 2πn, where n is an integer.

Equation 2:

The equation is sin(x) = 1/2.

Similar to the previous equation, we can use the unit circle or the inverse sine function to find the solutions.

The unit circle shows that the sine function is equal to 1/2 at two angles: π/6 and 5π/6.

Therefore, the solutions for sin(x) = 1/2 are:

- x = π/6 + 2πn, where n is an integer. - x = 5π/6 + 2πn, where n is an integer.

Please note that the solutions provided are general solutions. If you need specific solutions within a certain range, please provide more details.

Let me know if there's anything else I can help you with!