Question

Решить систему уравнения 3x-y=1 x^2-y=-1 фигурные скобочки

Answer 1

Вот так как-то , без ответа .
Там 0 и 3 ответ

Answer 2

Solution to the System of Equations

To solve the system of equations 3x - y = 1 and x^2 - y = -1, we can use the given equations to find the values of x and y that satisfy both equations.

Let's solve the system step by step:

1. From the first equation, 3x - y = 1, we can isolate y by subtracting 3x from both sides: -y = 1 - 3x.

2. From the second equation, x^2 - y = -1, we can substitute the value of y from the first equation into the second equation: x^2 - (1 - 3x) = -1.

3. Simplifying the equation, we have: x^2 - 1 + 3x = -1.

4. Rearranging the terms, we get: x^2 + 3x - 1 + 1 = 0.

5. Combining like terms, we have: x^2 + 3x = 0.

6. Factoring out x, we get: x(x + 3) = 0.

7. Setting each factor equal to zero, we have two possible solutions for x: - x = 0 - x + 3 = 0, which gives x = -3.

8. Now, we substitute these values of x back into the first equation to find the corresponding values of y: - For x = 0: 3(0) - y = 1. Solving for y, we get y = -1. - For x = -3: 3(-3) - y = 1. Solving for y, we get y = -10.

Therefore, the solutions to the system of equations are: - x = 0, y = -1 - x = -3, y = -10.

Please let me know if you need any further assistance!