Question

Самолет и вертолет, вылетев одновременно с одного и того же аэродрома для тушения пожара, находящегося на расстоянии 150 км от аэродрома, встретились через 30 минут, когда самолет уже возвращался на аэродром на расстоянии 50 км от пожара. Найдите скорости вертолета и самолета.

Answer 1

1) 150+50=200(км) пролетел самолет до встречи с вертолетом
2) 150-50=100(км) пролетел вертолет до встречи с самолетом
3) оба в полете находились 30 мин = 0,5 часа
4) 200 : 0,5 = 400(км/час) скорость самолета
5) 100 : 0,5 = 200(км/час) скорость вертолета

Answer 2

Problem Analysis

We are given that an airplane and a helicopter took off simultaneously from the same aerodrome to extinguish a fire located 150 km away from the aerodrome. They met after 30 minutes, at which point the airplane was already returning to the aerodrome and was 50 km away from the fire. We need to find the speeds of the helicopter and the airplane.

Solution

Let's assume the speed of the airplane is A km/h and the speed of the helicopter is H km/h.

We can use the formula: Speed = Distance / Time.

From the given information, we can calculate the following distances and times:

1. Distance covered by the airplane in 30 minutes (0.5 hours) = 50 km. 2. Distance covered by the helicopter in 30 minutes (0.5 hours) = 150 km - 50 km = 100 km.

Using the formula, we can set up the following equations:

1. For the airplane: A = 50 km / 0.5 hours. 2. For the helicopter: H = 100 km / 0.5 hours.

Let's calculate the speeds of the airplane and the helicopter.

Calculation

1. Speed of the airplane: - A = 50 km / 0.5 hours = 100 km/h.

2. Speed of the helicopter: - H = 100 km / 0.5 hours = 200 km/h.

Answer

The speed of the airplane is 100 km/h and the speed of the helicopter is 200 km/h.

Please let me know if I can help you with anything else.