Question

При каком условии графики функции y=kx-1 и y=px+5 пересекаются в точке Р(4;3)???

Answer 1

Y=kx-1 и y=px+5  Р(4;3)
3=4k-1
4k=4
k=1
3=4p+5
-2=4p
p= -1/2
Ответ: при k=1 и p= -1/2 графики функции пересекаются в точке Р(4;3)

Answer 2

Intersection of Functions at Point P(4, 3)

To find the conditions under which the functions y=kx-1 and y=px+5 intersect at the point P(4,3), we can use the fact that the two functions will intersect at the point P(4,3) if and only if they have the same y-coordinate when x=4.

The y-coordinate of the point P(4,3) should satisfy both functions simultaneously. This gives us the following equations:

1. For y=kx-1: - When x=4, y=k*4-1=3 - This gives us the equation 4k-1=3

2. For y=px+5: - When x=4, y=p*4+5=3 - This gives us the equation 4p+5=3

By solving these two equations, we can find the values of k and p for which the functions intersect at the point P(4,3).

Solving for k and p: 1. For y=kx-1: - 4k-1=3 - 4k=4 - k=1

2. For y=px+5: - 4p+5=3 - 4p=-2 - p=-0.5

Therefore, the functions y=kx-1 and y=px+5 intersect at the point P(4,3) when k=1 and p=-0.5.