Question

Пожалуйста срочно нужно решить две трубы, действует одновременно,заливают цистерну нефтью за 2ч.За сколько часов заполнят цистерну первая труба,действует отдельно,если ей для залива цистерны требуется на 3 ч меньше,чем другой?

Answer 1

Пусть вторая труба заполнит цистерну за х часов, тогда первая труба заполнит цистерну за х-3 часа.
 За 1 час вторая заполнит 1\х часть цистерны, а первая 1\(х-3) часть цистерны.
За 1 час обе трубы заполнят 1\2 часть цистерны.
Составим уравнение:
1\х + 1\(х-3) = 1\2
х²-7х+6=0
х=1 (не подходит по условию)
х=6.
Второй трубе потребуется 6 часов, тогда первой трубе потребуется
6-3=3 часа.
Ответ: 3 часа. 

Answer 2

Problem Statement

You have two pipes that are simultaneously filling an oil tanker in 2 hours. You want to know how long it will take for the first pipe to fill the tanker on its own, given that it takes 3 hours less than the other pipe.

Solution

To solve this problem, we can use the concept of work rates. Let's denote the time it takes for the first pipe to fill the tanker on its own as x hours. We are given that the second pipe fills the tanker in 3 hours more than the first pipe, so its time can be represented as x + 3 hours.

We know that when working together, the two pipes can fill the tanker in 2 hours. Using the concept of work rates, we can set up the following equation: 1/x + 1/(x+3) = 1/2

Let's solve for x using this equation.

Calculation

Using the equation 1/x + 1/(x+3) = 1/2, we can solve for x: ``` 1/x + 1/(x+3) = 1/2 (2(x+3) + 2x) / (x(x+3)) = 1 (2x + 6 + 2x) / (x^2 + 3x) = 1 4x + 6 = x^2 + 3x 0 = x^2 - x - 6 ``` Using the quadratic formula, we find: ``` x = (-(-1) ± √((-1)^2 - 4*1*(-6))) / (2*1) x = (1 ± √(1 + 24)) / 2 x = (1 ± √25) / 2 x = (1 ± 5) / 2 ``` We have two possible solutions for x: 1. x = (1 + 5) / 2 = 6/2 = 3 2. x = (1 - 5) / 2 = -4/2 = -2

Since time cannot be negative, the only valid solution is x = 3.

Answer

Therefore, the first pipe, working on its own, will fill the tanker in 3 hours.