
Мастер и его ученик изготовили 400 деталей. Сколько деталей готовил мастер, если известно, что
ученик изготовил на 100 деталей меньше? В первой бригаде рабочих было в 3 раза меньше, чем во второй, а в третьей- на 3 человека меньше, чем во второй. После того как в первую бригаду пришли 9 человек, кол-во рабочих в третьей бригадах стало одинаковым. Сколько всего рабочих в трех бригадах? Помогите хотя бы одну)))

Ответы на вопрос

1)Х+х-100=400
2х= 400+100
2х=500
Х= 500: 2
Х=250
2)250-100=150



Calculating the Number of Parts Made by the Master and the Apprentice
To solve this problem, we can use algebraic equations to represent the given information and solve for the unknowns.
Let's denote: - M as the number of parts made by the master. - A as the number of parts made by the apprentice.
Given that the apprentice made 100 parts less than the master, we can express this as: A = M - 100.
Also, we know that the total number of parts made is 400: M + A = 400.
By substituting the first equation into the second equation, we can solve for the number of parts made by the master.
M + (M - 100) = 400 2M - 100 = 400 2M = 500 M = 250.
So, the master made 250 parts and the apprentice made 150 parts.
Calculating the Total Number of Workers in Three Brigades
Let's denote: - x as the number of workers in the second brigade.
Given that the first brigade had three times fewer workers than the second brigade, and the third brigade had 3 fewer workers than the second brigade, we can express this as: - First brigade: 3x - Second brigade: x - Third brigade: x - 3
After 9 workers joined the first brigade, the number of workers in the third brigade became equal to the number in the second brigade.
So, we can set up the equation: 3x + 9 = x - 3.
Solving for x: 2x = -12 x = -6.
Since the number of workers cannot be negative, there seems to be a mistake in the information provided. If you have additional details or if there was an error in the information, please provide the correct information, and I'd be happy to help further.


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