Question

2(x+3)-4x<-10 Другим способом с и x вправо с силами влево

Answer 1

Y=-3x²+7x+1 -5=-3x²+7x+1 3x²-7x-1-5=0 3x²-7x-6=0 D=(-7)²-4*3*(-6)=49+72=121 x₁=(7-11)/6=-4/6=-2/3 x₂=(7+11)/6=3 Ответ: при х=-2/3 и х=3 y=x²+4x+3 а) при х=1 и х=-5 б) (-∞;-3]∪[-1;∞) в) (-∞;-2]

Answer 2

I can help you with your math problem. Here is one way to solve it:

We want to isolate x on the right side of the inequality, so we need to move the constants to the left side. To do this, we can subtract 6 from both sides, and then add 4x to both sides. This gives us:

$$2(x+3)-4x<-10$$ $$2x+6-4x<-10$$ $$-2x+6<-10$$ $$-2x+6-6<-10-6$$ $$-2x<-16$$ $$-2x+4x<-16+4x$$ $$2x<-16$$

Now, we need to divide both sides by 2 to get x alone. However, since we are dividing by a negative number, we need to flip the direction of the inequality sign. This gives us:

$$\frac{2x}{2}>\frac{-16}{2}$$ $$x>-8$$

Therefore, the solution is $$x>-8$$.

I hope this helps. If you have any other questions, feel free to ask me.Ответь+подробно.+2(x+3)-4x<-10+Другим+способом+с+и+x+вправо+с+силами+влево