Question

при каких значениях x значение многочленов 7x^2+13x+2 и 5x^2-22x -2 равны?

Answer 1

7x²+13x+2=5x²-22x-2
 2x²+35x+4=0    D=35²-4*2*4=1225-32=1193
 корень не извлекается видимо ошибка в условии
  х1=-35-√1193)/4     х2= -35+√1193)/4

Answer 2

Finding the Values of x for the Given Polynomial Equations

The given polynomial equations are: - \(7x^2 + 13x + 2\) - \(5x^2 - 22x - 2\)

To find the values of \(x\) for which the values of these polynomials are equal, we can set the two polynomial equations equal to each other and solve for \(x\).

Setting the two polynomial equations equal to each other: \[7x^2 + 13x + 2 = 5x^2 - 22x - 2\]

Solving for \(x\): \[7x^2 + 13x + 2 = 5x^2 - 22x - 2\] \[7x^2 - 5x^2 + 13x + 22x + 2 + 2 = 0\] \[2x^2 + 35x + 4 = 0\]

Using the quadratic formula to solve for \(x\: \[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}\] where \(a = 2\), \(b = 35\), and \(c = 4\).

Calculating the values of \(x\) using the quadratic formula: \[x = \frac{{-35 \pm \sqrt{{35^2 - 4*2*4}}}}{{2*2}}\] \[x = \frac{{-35 \pm \sqrt{{1225 - 32}}}}{{4}}\] \[x = \frac{{-35 \pm \sqrt{{1193}}}}{{4}}\]

The values of \(x\) for which the given polynomial equations are equal are: - \(x = \frac{{-35 + \sqrt{{1193}}}}{{4}}\) - \(x = \frac{{-35 - \sqrt{{1193}}}}{{4}}\)

The values of \(x\) for which the values of the given polynomial equations are equal are \(\frac{{-35 + \sqrt{{1193}}}}{{4}}\) and \(\frac{{-35 - \sqrt{{1193}}}}{{4}}.