Question

3. Первая труба пропускает на 5 литров воды в минуту меньше, чем вторая. Сколько литров воды в минуту пропускает вторая труба, если резервуар объемом 375 литров она заполняет на 10 минут быстрее, чем первая труба заполняет резервуар объемом 500 литров?

Answer 1

X  1 ая трубаx+5 2 ая труба 500/x-375/(x+5)=10500x+2500-375x=10x^2+50x10x^2-75x-2500=02x^2-15-500=0 D=(-15)^2-4*2*(-500)=4225 x1=15+65/4=20x2=15-65/4=-12.5 -12.5 - не удовлетворяет условию  20+5=25л/мин пропускает 2ая турба

Answer 2

Problem Analysis

We are given that the first pipe can fill a reservoir with a volume of 500 liters in 10 minutes. The second pipe fills the same reservoir in 10 minutes minus the time it takes for the first pipe to fill a reservoir with a volume of 375 liters. We need to find the rate at which the second pipe fills the reservoir.

Solution

Let's assume that the rate at which the second pipe fills the reservoir is x liters per minute.

According to the given information, the first pipe fills the reservoir with a volume of 500 liters in 10 minutes. Therefore, the rate of the first pipe is 500 liters / 10 minutes = 50 liters per minute.

We are also given that the first pipe fills a reservoir with a volume of 375 liters in 10 minutes more than the second pipe takes to fill the same reservoir. This can be expressed as:

375 liters / (x liters per minute) = 10 minutes + 10 minutes

Simplifying the equation, we have:

375 / x = 20

To find the value of x, we can cross-multiply and solve for x:

375 = 20x

x = 375 / 20 = 18.75 liters per minute

Therefore, the second pipe fills the reservoir at a rate of 18.75 liters per minute.

Answer

The second pipe fills the reservoir at a rate of 18.75 liters per minute.