Question

3x/4-x=4x/5+x Помогите решить и пожалуйста объяснение.

Answer 1

$\frac{3x}{4-x} = \frac{4x}{5+x}$
$\frac{3x}{4-x} - \frac{4x}{5+x}=0$
$\frac{15x+3x^2}{(4-x)(5+x)} - \frac{16x-4x^2}{(4-x)(5+x)}=0$
$\frac{7x^2-x}{(4-x)(5+x)}=0$
$\frac{x(7x-1)}{(4-x)(5+x)}=0. x_1=0; x_2= \frac{1}{7}$

Answer 2

Solving the Equation 3x/4 - x = 4x/5 + x

To solve the equation 3x/4 - x = 4x/5 + x, we'll follow these steps:

1. Combine like terms on both sides of the equation. 2. Solve for the variable x.

Step 1: Combine Like Terms

First, let's combine like terms on both sides of the equation.

3x/4 - x = 4x/5 + x

To combine the terms, we can first convert all the terms to have a common denominator. The common denominator for 4 and 5 is 20. So, we can rewrite the equation with the common denominator:

15x/20 - 20x/20 = 16x/20 + 20x/20

Now, the equation becomes:

15x/20 - 20x/20 = 16x/20 + 20x/20 -5x/20 = 36x/20

Step 2: Solve for x

Now, let's solve for the variable x.

-5x/20 = 36x/20

To solve for x, we can multiply both sides of the equation by 20 to get rid of the denominators:

-5x = 36x -5x - 36x = 0 -41x = 0

Finally, we can solve for x by dividing both sides by -41:

x = 0/(-41) x = 0

So, the solution to the equation 3x/4 - x = 4x/5 + x is x = 0.

This solution is obtained by combining like terms and solving for the variable x.