Question

Два велосипедиста отправились одновременно навстречу друг другу из пунктов,расстояние между которыми 60 км,и встретились через 2 часа.Определите скорость каждого велосипедиста,если у одного она на 2 км/ч больше,чем у другого.

Answer 1

х- скорость одного

х+2- скорость второго

х+х+2=60/2

2х+2=30

2х=30-2

2х=28

х=28/2

х=14

14 км/ч- скорость одного

14+2=16км/ч- скорость второго 

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from two points and meet each other after 2 hours. The distance between the two points is 60 km. One cyclist's speed is 2 km/h greater than the other cyclist's speed. We need to determine the speed of each cyclist.

Solution

Let's assume the speed of the slower cyclist is x km/h. Then the speed of the faster cyclist will be x + 2 km/h.

We can use the formula speed = distance / time to calculate the speeds of the two cyclists.

The slower cyclist covers a distance of 60 km in 2 hours, so their speed is 60 / 2 = 30 km/h.

The faster cyclist's speed is 2 km/h greater than the slower cyclist's speed, so their speed is 30 + 2 = 32 km/h.

Therefore, the speed of the slower cyclist is 30 km/h and the speed of the faster cyclist is 32 km/h.

Answer

The speed of the slower cyclist is 30 km/h and the speed of the faster cyclist is 32 km/h.