Question

Помогите Решите уравнение (x-1)+2x^2=0

Answer 1

2x^2 + x - 1 = 0 
D = 1 +  8= 9 
x₁ = ( - 1 + 3)/4 = 0,5;
x₂ = ( - 1 - 3)/4 = - 1;

Answer 2

(х-1)+2х^2=0
2х^2+x-1=0
D=1-4*2*(-1)=3
x1=-1+3/4=2/4=1/2
x2=-1-1/4=-1

Answer 3

I can help you solve the equation $(x-1)+2x^2=0$. To do that, we need to use the quadratic formula, which is:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

In this case, we have $a=2$, $b=-1$, and $c=0$. Plugging these values into the formula, we get:

$$x = \frac{1 \pm \sqrt{1 - 4 \cdot 2 \cdot 0}}{4}$$

Simplifying, we get:

$$x = \frac{1 \pm 1}{4}$$

Therefore, the two solutions are:

$$x = \frac{1 + 1}{4} = \frac{1}{2}$$

and

$$x = \frac{1 - 1}{4} = 0$$

I hope this helps you understand how to solve the equation. If you have any other questions, feel free to ask me.Ответь+подробно.++Помогите+Решите+уравнение+(x-1)+2x^2=0+