Question

(11-12x)^2=9 (4+x)^2=3 (7+7x)^2=0 (20x+40)^2=-100

Answer 1

Ответ:

.....

Объяснение:

...............................

Answer 2

Ответ:

Объяснение:

1)(11-12x)^2=9

11-12x=-3  либо 11-12x=3

-12x=-3-11 либо -12x=3-11

-12x=-14 либо -12x=-8

х=-14/-12 либо х=-8/-12

х=1 1/6  либо 2/3

Ответ: 2/3;1 1/6;

2) (4+x)^2=3

   4+x=-√3 либо 4+x=√3

х=-√3 -4 либо х=√3 -4

Ответ:-√3-4;√3 -4;

3 )(7+7x)^2=0

       7+7x=0

       7x=-7

   х=-7/7

  х=-1

Ответ: -1;

4) 20x+40)^2=-100  - уравнение не имеет корней так как квадрат числа не может быть отрицательным

Ответ: нет решения;

Answer 3

Let's solve each of these equations step by step:

1. (11 - 12x)^2 = 9

To solve this equation, expand and simplify:

(11 - 12x)^2 = 9 121 - 264x + 144x^2 = 9

Now, subtract 9 from both sides:

144x^2 - 264x + 121 - 9 = 0

144x^2 - 264x + 112 = 0

Now, we can use the quadratic formula to solve for x:

x = [-(-264) ± √((-264)^2 - 4(144)(112))] / (2 * 144)

x = [264 ± √(69696 - 64512)] / 288

x = [264 ± √5184] / 288

x = [264 ± 72] / 288

Now, we can find two possible values for x:

1. x = (264 + 72) / 288 = 336 / 288 = 7/6
2. x = (264 - 72) / 288 = 192 / 288 = 2/3

So, the solutions are x = 7/6 and x = 2/3.

2. (4 + x)^2 = 3

To solve this equation, expand and simplify:

(4 + x)^2 = 3 16 + 8x + x^2 = 3

Now, subtract 3 from both sides:

x^2 + 8x + 16 - 3 = 0

x^2 + 8x + 13 = 0

Now, we can use the quadratic formula to solve for x:

x = [-8 ± √(8^2 - 4(1)(13))] / (2 * 1)

x = [-8 ± √(64 - 52)] / 2

x = [-8 ± √12] / 2

x = [-8 ± 2√3] / 2

Now, simplify:

x = -4 ± √3

So, the solutions are x = -4 + √3 and x = -4 - √3.

3. (7 + 7x)^2 = 0

To solve this equation, simply take the square root of both sides:

7 + 7x = 0

Now, subtract 7 from both sides:

7x = -7

Divide by 7:

x = -1

So, the solution is x = -1.

4. (20x + 40)^2 = -100

This equation has no real solutions because the square of any real number is always non-negative (greater than or equal to zero), and the right side of the equation is negative (-100). Therefore, there are no real solutions for this equation.