Question

X(В квадрате)+9x-10>/0

Answer 1

X²+9x-10≥0
x1+x2=-9 U x1*x2=-10
x1=-10 U x2=1
   +                  _                       +
------[-10]--------------------[1]--------------
x∈(-∞;-10] U [1;∞)

Answer 2

I believe there might be a typo in the inequality you provided. It seems like there is an extra symbol after the expression "X(В квадрате)+9x-10", which makes the inequality invalid. It should be in the form of a complete inequality, like greater than (>) or less than (<).

If you meant to write a quadratic inequality in the form of $X^2 + 9x - 10 > 0$, then I can help you solve it.

To solve the inequality $X^2 + 9x - 10 > 0$, we need to find the intervals for which the expression is greater than zero.

Step 1: Factor the quadratic expression: $X^2 + 9x - 10 = (X + 10)(X - 1)$

Step 2: Find the critical points where the expression equals zero: $X + 10 = 0 \Rightarrow X = -10$ and $X - 1 = 0 \Rightarrow X = 1$

Step 3: Create a sign chart for the intervals:

Interval	$X + 10$	$X - 1$	$X^2 + 9x - 10$
$X < -10$	-	-	+
$-10 < X < 1$	+	-	-
$X > 1$	+	+	+

Step 4: Analyze the sign chart to determine the solution: The inequality is satisfied when $X < -10$ and $X > 1$ since the expression $X^2 + 9x - 10$ is positive in those intervals.

So, the solution to the inequality is $X < -10$ or $X > 1$.