Question

Sin2d/1-cos2d срочно ​

Answer 1

Ответ:

ctgd

Объяснение:

$\frac{sin2d}{1-cos2d}=\frac{2sind*cosd}{1-(cos^2d-sin^2d)}=\frac{2sind*cosd}{1-cos^2d+sin^2d}=\frac{2sind*cosd}{(1-cos^2d)+sin^2d}=\frac{2sind*cosd}{sin^2d+sin^2d}=\frac{2sind*cosd}{2sin^2d}=\frac{cosd}{sind}=ctgd$

Answer 2

sin1d=cos1d

cos1d-sin2d=cos2/1sin2d

Answer 3

To simplify the expression $\frac{\sin^2 d}{1 - \cos^2 d}$, we can use the trigonometric identity $\sin^2 d = 1 - \cos^2 d$. This identity is derived from the Pythagorean identity for sine and cosine.

So, the expression becomes:

$\frac{\sin^2 d}{1 - \cos^2 d} = \frac{1 - \cos^2 d}{1 - \cos^2 d}$

Now, since the numerator and denominator are the same, they cancel out:

$\frac{1 - \cos^2 d}{1 - \cos^2 d} = 1$

Therefore, the simplified expression is $1$.