Question

Cos(-1845градусов ) * sin(23пи/6)

Answer 1

Ответ:

$- \frac{ \sqrt{2} }{4}$

Объяснение:

$= \cos( - \frac{41\pi}{4} ) \times \frac{1}{2} = \frac{ \sqrt{2} }{2} \times ( - \frac{1}{2} ) = - \frac{ \sqrt{2} }{4}$

Answer 2

To evaluate the expression, we need to find the trigonometric values for the given angles and then perform the calculations.

1. Let's find the trigonometric values for the given angles:

Cos(-1845 degrees) is equivalent to Cos(360 degrees * (-5) + (-45 degrees)).

Since the cosine function has a period of 360 degrees, we can simplify this to Cos(-45 degrees).

Now, let's find the value of Cos(-45 degrees): Cos(-45 degrees) = Cos(45 degrees) [Cosine function is an even function] Cos(45 degrees) = 1/sqrt(2) (approx 0.70710678)

2. Now, let's find the value of sin(23π/6):

23π/6 is equivalent to 3π + π/6.

Since the sine function has a period of 2π, we can simplify this to sin(π/6).

Now, let's find the value of sin(π/6): sin(π/6) = 1/2

3. Now, we can perform the final calculation: Cos(-1845 degrees) * sin(23π/6) = (1/sqrt(2)) * (1/2) ≈ 0.35355339

Therefore, Cos(-1845 degrees) * sin(23π/6) is approximately equal to 0.35355339.