Question

2sin(П/6-3x)-1=0!!!!!!!!!!!!!!

Answer 1

Объяснение:

решение на фото.................

Answer 2

To solve the equation 2sin(π/6 - 3x) - 1 = 0, we can follow these steps:

Step 1: Add 1 to both sides of the equation to isolate the sin function: 2sin(π/6 - 3x) = 1

Step 2: Divide both sides of the equation by 2: sin(π/6 - 3x) = 1/2

Step 3: Take the inverse sine (sin^(-1)) of both sides to eliminate the sine function: π/6 - 3x = sin^(-1)(1/2)

Step 4: Evaluate the inverse sine: π/6 - 3x = π/6 or π - (π/6)

Step 5: Solve for x in each case:

For π/6 - 3x = π/6: Subtract π/6 from both sides: -3x = 0 Divide by -3: x = 0

For π/6 - 3x = π - (π/6): Combine like terms on the right side: π/6 - 3x = 5π/6 Subtract π/6 from both sides: -3x = 5π/6 - π/6 Simplify the right side: -3x = 4π/6 Divide by -3: x = -4π/18 Simplify the fraction: x = -2π/9

Therefore, the solutions to the equation 2sin(π/6 - 3x) - 1 = 0 are x = 0 and x = -2π/9.