Question

(3x- у в кв.)×(3x-y в кв.)​

Answer 1

Ответ:

решение смотри на фотографии

Объяснение:

Answer 2

$(3x - {y}^{2} )(3x - {y}^{2} ) = (3x - {y}^{2} )^{2} = 9 {x}^{2} - 6x {y}^{2} + {y}^{4}$

Answer 3

To multiply the expression (3x - y)^2 by itself, we can use the FOIL method, which stands for First, Outer, Inner, Last. Let's break down the steps:

(3x - y)^2 can be expanded as (3x - y) * (3x - y).

First: Multiply the first terms of each binomial. (3x) * (3x) = 9x^2

Outer: Multiply the outer terms of each binomial. (3x) * (-y) = -3xy

Inner: Multiply the inner terms of each binomial. (-y) * (3x) = -3xy

Last: Multiply the last terms of each binomial. (-y) * (-y) = y^2

Now, let's combine the results:

9x^2 - 3xy - 3xy + y^2

Simplifying further:

9x^2 - 6xy + y^2

So, the product of (3x - y)^2 and (3x - y)^2 is 9x^2 - 6xy + y^2.