Question

Б)(2х/5х-10) -х/(х-2) в)(а-2) квадрат деленное на (3а-6)/(2в+10)

Answer 1

Ответ:

р а в н о6

Объяснение:

Answer 2

To simplify the given expressions, let's work through each step:

а) Simplify (2х)/(5х - 10) - х/(х - 2):

Step 1: Factor the denominators 5х - 10 can be factored as 5(x - 2) х - 2 is already factored

Step 2: Find the common denominator, which is 5(x - 2) So the expression becomes: (2х)/(5(x - 2)) - х/(x - 2)

Step 3: Combine the fractions: [(2х) - х] / (5(x - 2))

Step 4: Simplify the numerator: (2х - х) / (5(x - 2)) х / (5(x - 2))

b) Simplify (а - 2)^2 / (3а - 6) / (2в + 10):

Step 1: Simplify the numerator (а - 2)^2: (а - 2)^2 = (а - 2) * (а - 2) = а^2 - 4а + 4

Step 2: Factor the denominator (3а - 6): 3а - 6 can be factored as 3(а - 2)

Step 3: Simplify the expression: (а^2 - 4а + 4) / 3(а - 2) / (2в + 10)

Step 4: Invert the second fraction and multiply: (а^2 - 4а + 4) / 3(а - 2) * (2в + 10)

Step 5: Distribute the denominator: (а^2 - 4а + 4) * (2в + 10) / 3(а - 2)

Step 6: Expand the numerator: (2ва^2 + 10а - 4а^2 - 20а + 4) / 3(а - 2)

Step 7: Combine like terms: (2ва^2 - 4а^2 + 10а - 20а + 4) / 3(а - 2)

Step 8: Simplify further: (-2а^2 - 10а + 4) / 3(а - 2)

So, the simplified expression is (-2а^2 - 10а + 4) / (3(а - 2)).