
5x+11y=21,8x-23y=-7


Ответы на вопрос

Объяснение:
5х+11у=21
5х+11у-21=21-21
5х+11у-21=0
8х-23у=-7
8х-23у+7=-7+7
8х-23у+7=0



It looks like you've provided a system of two linear equations with two variables:
Equation 1: 5x + 11y = 21 Equation 2: 8x - 23y = -7
To solve for the values of x and y that satisfy both equations simultaneously, you can use methods like substitution, elimination, or matrix operations. Let's use the elimination method to solve this system:
Multiply both sides of Equation 1 by 8, and both sides of Equation 2 by 5 to make the coefficients of x in both equations equal:
Equation 1 (multiplied by 8): 40x + 88y = 168 Equation 2 (multiplied by 5): 40x - 115y = -35
Now, subtract Equation 2 from Equation 1 to eliminate the x terms:
(40x + 88y) - (40x - 115y) = 168 - (-35) 40x + 88y - 40x + 115y = 168 + 35 203y = 203
Divide both sides by 203:
y = 1
Now that we know the value of y, we can substitute it back into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1:
5x + 11(1) = 21 5x + 11 = 21 5x = 10 x = 2
So, the solution to the system of equations is x = 2 and y = 1. The values (x = 2, y = 1) satisfy both Equation 1 and Equation 2.


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