Question

4x^4-x^2=0 хелп плиз

Answer 1

Ответ:

Объяснение:

4x^4-x^2=0

x^2(4x^2-1)=0

x^2=0 или 4x^2-1=0

x=0  x=±1/2

ответ:x₁= -1/2; x₂= 0 ; x₃= 1/2

Answer 2

Sure, I'd be happy to help! The equation you provided is a quadratic equation in terms of x. Let's solve it step by step:

4x^4 - x^2 = 0

First, notice that both terms have x^2 as a common factor. Factor out x^2:

x^2(4x^2 - 1) = 0

Now we have a quadratic expression inside the parentheses: 4x^2 - 1. This can be factored further:

(2x)^2 - 1^2 = 0 (2x + 1)(2x - 1) = 0

Now, apply the zero product property: if the product of two factors is zero, at least one of the factors must be zero.

2x + 1 = 0 or 2x - 1 = 0

Solve for x in each equation:

For 2x + 1 = 0: 2x = -1 x = -1/2

For 2x - 1 = 0: 2x = 1 x = 1/2

So, the solutions to the equation 4x^4 - x^2 = 0 are x = -1/2 and x = 1/2.