Question

(b-4)x²+(2b-8)x+15=0

Answer 1

типа вот так надо ответ я проверял

Answer 2

To solve the quadratic equation (b-4)x² + (2b-8)x + 15 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Comparing the equation to the standard quadratic form ax² + bx + c = 0, we have: a = (b - 4) b = (2b - 8) c = 15

Substituting these values into the quadratic formula, we get:

x = (-(2b - 8) ± √((2b - 8)² - 4(b - 4)(15))) / (2(b - 4))

Simplifying further:

x = (8 - 2b ± √(4b² - 32b + 64 - 60b + 240)) / (2b - 8) x = (8 - 2b ± √(4b² - 92b + 304)) / (2b - 8) x = (8 - 2b ± √(4(b² - 23b + 76))) / (2b - 8) x = (8 - 2b ± √(4(b - 19)(b - 4))) / (2b - 8)

Now, we can simplify the expression further and solve for x:

x = (8 - 2b ± 2√((b - 19)(b - 4))) / (2b - 8) x = (4 - b ± √((b - 19)(b - 4))) / (b - 4)

These are the solutions to the quadratic equation (b-4)x² + (2b-8)x + 15 = 0, given in terms of b.