Question

(3a⁻¹ b³) · (6a⁻²b⁻³)²=

Answer 1

Данный ответ представлен фотографией.

Answer 2

Ответ:

все на фотографии

Объяснение:

желаю успехов

Answer 3

To simplify the expression (3a⁻¹ b³) · (6a⁻²b⁻³)², we can apply the rules of exponents and multiplication. Let's break it down step by step:

First, let's simplify each term individually: (3a⁻¹ b³) = 3/a · b³ (6a⁻²b⁻³)² = (6/a²) · (1/b³)² = (6/a²) · (1/b⁶) = 6/(a²b⁶)

Now, let's multiply the two simplified terms: (3/a · b³) · (6/(a²b⁶)) = (3 · 6)/(a · a² · b³ · b⁶)

Next, let's simplify the denominator: a · a² = a³ (using the rule a^m · a^n = a^(m+n)) b³ · b⁶ = b⁹ (using the rule b^m · b^n = b^(m+n))

Substituting these simplifications back into the expression: (3 · 6)/(a³ · b⁹) = 18/(a³b⁹)

So, the simplified expression is 18/(a³b⁹).