Question

X^(2)+y^(2)-2x+6y+11

Answer 1

Ответ:

х-6у=-2

2х+3у=11

х=-2+6у

2(-2+6у)+3у=11

-4+12у+3у=11

15у=11+4

15у=15

у=15/15

у=1

х-6*1=-2

х-6=-2

х=-2+6

х=4

у=1 х=4

Answer 2

The expression you've provided, X^2 + y^2 - 2x + 6y + 11, appears to be an equation in terms of the variables x and y. To provide more information, I'll assume you want to understand its characteristics. This looks like an equation for a circle with some additional constants:

The equation can be written in the standard form of a circle as:

(x^2 - 2x) + (y^2 + 6y) = -11

To complete the square for both x and y, we can manipulate the equation as follows:

1. For x^2 - 2x: x^2 - 2x = (x^2 - 2x + 1) - 1 = (x - 1)^2 - 1

2. For y^2 + 6y: y^2 + 6y = (y^2 + 6y + 9) - 9 = (y + 3)^2 - 9

Now, we can rewrite the equation as:

(x - 1)^2 + (y + 3)^2 = -11 + 1 - 9 = -19

So, the equation represents a circle centered at (1, -3) with a radius of √19, and it is located in the xy-plane with its center above and to the right of the origin. However, it's worth noting that the right side of the equation is negative, which means there is no real solution for this equation when dealing with real numbers. In the complex plane, it would represent an imaginary circle.

The general form of a circle equation is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is its radius.