Question

24 - ( 3 у + 1 ) ( 4 у - 5 ) = ( 11 - 6 у ) ( 2 у - 1 ) + 6​

Answer 1

Ответ:

Пожалуйста, сначала думал что по дискреминанту, но в итоге нет, ошибся)

Answer 2

Let's solve the equation step by step:

Given equation: 24 - (3y + 1)(4y - 5) = (11 - 6y)(2y - 1) + 6

First, let's simplify the equation by multiplying the expressions on both sides:

24 - (3y + 1)(4y - 5) = (11 - 6y)(2y - 1) + 6

Expanding the expressions on both sides:

24 - (12y^2 - 17y + 4y - 5) = (22y^2 - 11y - 12y^2 + 6y) + 6

Now, simplify further by combining like terms within each parenthesis:

24 - (12y^2 - 13y - 5) = (10y^2 - 5y) + 6

Now, distribute the negative sign inside the first set of parentheses:

24 - 12y^2 + 13y + 5 = 10y^2 - 5y + 6

Now, continue to simplify by collecting like terms on both sides of the equation:

24 + 5 = 10y^2 - 12y^2 + 13y - 5y + 6

29 = -2y^2 + 8y + 6

Now, subtract 29 from both sides to isolate the terms on the right side:

-2y^2 + 8y + 6 - 29 = 0

Simplify further:

-2y^2 + 8y - 23 = 0

Now, let's solve this quadratic equation. You can use the quadratic formula:

y = (-b ± √(b² - 4ac)) / (2a)

In this case, a = -2, b = 8, and c = -23. Plug these values into the formula:

y = (-8 ± √(8² - 4(-2)(-23))) / (2(-2))

y = (-8 ± √(64 - 184)) / (-4)

y = (-8 ± √(-120)) / (-4)

The term inside the square root is negative, which means there are no real solutions to this quadratic equation. The solutions would be complex numbers.

So, the equation has no real solutions for "y."