Question

3(2x-5)²-4(3-2x)²+4x²=0​

Answer 1

12х²-60х+75-36+48х-16х²+4х²=0

12х=39

х=13/4=3.25

Answer 2

To solve the quadratic equation 3(2x-5)² - 4(3-2x)² + 4x² = 0, you can follow these steps:

1. Expand the squared terms: 3(4x² - 20x + 25) - 4(9 - 12x + 4x²) + 4x² = 0

2. Distribute the constants: 12x² - 60x + 75 - 36 + 48x - 16x² + 4x² = 0

3. Combine like terms: (12x² - 16x² + 4x²) + (-60x + 48x) + (75 - 36) = 0

4. Simplify further: (0x²) + (-12x) + (39) = 0

5. Now, you have a simple linear equation: -12x + 39 = 0

6. Subtract 39 from both sides to isolate -12x: -12x = -39

7. Finally, divide by -12 to solve for x: x = -39 / -12

Simplify the right side: x = 13/4

So, the solution to the equation is x = 13/4.