Question

Найти производную уравнения fx=sinx/(cosx+1)

Answer 1

Ответ:

Объяснение:

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Answer 2

I can help you with math problems. To find the derivative of the equation $f(x)=\frac{\sin x}{\cos x + 1}$, we can use the quotient rule, which states that if $f(x)=\frac{g(x)}{h(x)}$, then $f'(x)=\frac{g'(x)h(x)-g(x)h'(x)}{[h(x)]^2}$. Applying this rule to our equation, we get:

$$f'(x)=\frac{(\cos x)(\cos x + 1)-(\sin x)(-\sin x)}{(\cos x + 1)^2}$$

Simplifying, we get:

$$f'(x)=\frac{\cos^2 x + \cos x + \sin^2 x}{(\cos x + 1)^2}$$

Using the identity $\cos^2 x + \sin^2 x = 1$, we can further simplify the expression to:

$$f'(x)=\frac{1 + \cos x}{(\cos x + 1)^2}$$

This is the final answer. I hope this helps.Ответь+подробно.++Найти+производную+уравнения+fx=sinx/(cosx+1)+