Question

2)(x-1)^2= 1-2 (X+3)​

Answer 1

Ответ:

±корень из 6

Объяснение:

${(x - 1)}^{2} = 1 - 2(x - 3) \\ {x}^{2} - 2x + 1 = 1 - 2x + 6 \\ {x}^{2} = 6 \\ x = \sqrt{6} \: \: \: \: \: \: x = - \sqrt{6}$

Answer 2

Let's solve the equation step by step:

1. Expand the squared term on the left side: (x - 1)^2 = (x - 1)(x - 1) = x^2 - 2x + 1

2. Distribute the -2 on the right side: 1 - 2(x + 3) = 1 - 2x - 6 = -2x - 5

Now the equation becomes: x^2 - 2x + 1 = -2x - 5

3. Move all terms to one side to set the equation to zero: x^2 - 2x + 2x + 1 + 5 = 0

Simplifying the equation: x^2 + 6 = 0

4. Subtract 6 from both sides: x^2 = -6

At this point, we have a quadratic equation with no real solutions since the square of any real number cannot be negative. Therefore, the given equation has no real solutions.