Question

2) -x² - 6x + 19 = 0;​

Answer 1

Ответ:

-x² - 6x=0-19

-x²-6x= -19

-x³ = -19-6

-x³ =-25

-x=-25:3

-x=-8,3

Answer 2

To solve the quadratic equation -x² - 6x + 19 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = -1, b = -6, and c = 19. Plugging these values into the formula, we get:

x = (-(-6) ± √((-6)² - 4(-1)(19))) / (2(-1)) x = (6 ± √(36 + 76)) / (-2) x = (6 ± √112) / (-2)

Simplifying further, we have:

x = (6 ± √(16 * 7)) / (-2) x = (6 ± 4√7) / (-2)

Now we can simplify and find the two possible solutions:

x₁ = (6 + 4√7) / (-2) x₁ = -3 - 2√7

x₂ = (6 - 4√7) / (-2) x₂ = -3 + 2√7

Therefore, the solutions to the quadratic equation -x² - 6x + 19 = 0 are:

x₁ = -3 - 2√7 x₂ = -3 + 2√7