Question

((x + y)xy = 6 lxy + x + y = 5

Answer 1

Я только первый премьер смогла решить

Answer 2

To solve the given system of equations:

Equation 1: (x + y)xy = 6 Equation 2: lxy + x + y = 5

Let's rearrange Equation 1 and simplify it:

(x + y)xy = 6 x^2y + xy^2 = 6

Now, let's solve Equation 2 for l:

lxy + x + y = 5 lxy = 5 - x - y

Substitute the expression for lxy in Equation 1:

x^2y + xy^2 = 6 (5 - x - y)xy = 6

Expand the expression:

5xy - x^2y - xy^2 = 6

Rearrange the equation to a quadratic form:

x^2y + xy^2 - 5xy + 6 = 0

This is a quadratic equation in terms of xy. To solve it, we can factorize it:

(xy - 2)(xy - 3) = 0

Setting each factor to zero gives us two cases:

Case 1: xy - 2 = 0 xy = 2

Case 2: xy - 3 = 0 xy = 3

Now, we can solve for x and y separately using these values of xy.

For Case 1: xy = 2

Substituting xy = 2 into Equation 2:

l(2) + x + y = 5 2l + x + y = 5

We don't have enough information to find exact values for x and y in this case.

For Case 2: xy = 3

Substituting xy = 3 into Equation 2:

l(3) + x + y = 5 3l + x + y = 5

Similarly, we don't have enough information to find exact values for x and y in this case either.

Therefore, based on the given information, we cannot determine the exact values of x and y that satisfy both equations simultaneously.