Question

Y=2x/x-2–3 ;x0=1 Формула: y=f’(x2)+f’(x)(x-x2)

Answer 1

это сразу решение

y=2*1-2-3

y=2-2-3

y=-3

Объяснение

ответ выполнен с начинающими если не правильно извини

ставь лайк пж я старался или хотя бы звёзда

Answer 2

To use the formula y = f'(x2) + f'(x)(x - x2), we need to find the derivatives of the function f(x) = 2x / (x - 2) - 3 and evaluate them at x = x2.

Let's start by finding the derivative of f(x):

f(x) = 2x / (x - 2) - 3

Using the quotient rule, we have:

f'(x) = [2(x - 2) - 2x] / (x - 2)^2 = [2x - 4 - 2x] / (x - 2)^2 = -4 / (x - 2)^2

Now, let's evaluate f'(x2):

f'(x2) = -4 / (x2 - 2)^2

Substituting x2 = 1 into the expression:

f'(1) = -4 / (1 - 2)^2 = -4 / (-1)^2 = -4

Finally, we can use the formula y = f'(x2) + f'(x)(x - x2) and substitute the values we have calculated:

y = f'(1) + f'(x)(x - 1)

Since we don't have a specific value for x, we can leave it in the equation as it is.