Question

ДАМ 20 БАЛЛОВ выполнить умножение г) (x - 3y)(x + 6y). д) (3k - 1)(3k - 1); e) (x³ + 5y) (x³ + 5y)​

Answer 1

Ответ:

г)х^2 + 6у -3ху -16у^2. Д) 9к^2 - 3к +1 -3

Объяснение:

Answer 2

г) (x - 3y)(x + 6y)

To multiply these binomials, we can use the FOIL method, which stands for First, Outer, Inner, Last. Let's apply it:

First: Multiply the first terms of each binomial. (x)(x) = x²

Outer: Multiply the outer terms of each binomial. (x)(6y) = 6xy

Inner: Multiply the inner terms of each binomial. (-3y)(x) = -3xy

Last: Multiply the last terms of each binomial. (-3y)(6y) = -18y²

Now, we can combine these terms:

x² + 6xy - 3xy - 18y²

Simplifying the middle terms:

x² + 3xy - 18y²

So, the result of (x - 3y)(x + 6y) is x² + 3xy - 18y².

д) (3k - 1)(3k - 1)

Using the FOIL method again:

First: Multiply the first terms of each binomial. (3k)(3k) = 9k²

Outer: Multiply the outer terms of each binomial. (3k)(-1) = -3k

Inner: Multiply the inner terms of each binomial. (-1)(3k) = -3k

Last: Multiply the last terms of each binomial. (-1)(-1) = 1

Now, let's combine these terms:

9k² - 3k - 3k + 1

Simplifying the middle terms:

9k² - 6k + 1

Therefore, the result of (3k - 1)(3k - 1) is 9k² - 6k + 1.

e) (x³ + 5y)(x³ + 5y)

Using the FOIL method once again:

First: Multiply the first terms of each binomial. (x³)(x³) = x^6

Outer: Multiply the outer terms of each binomial. (x³)(5y) = 5x³y

Inner: Multiply the inner terms of each binomial. (5y)(x³) = 5x³y

Last: Multiply the last terms of each binomial. (5y)(5y) = 25y²

Now, let's combine these terms:

x^6 + 5x³y + 5x³y + 25y²

Simplifying the middle terms:

x^6 + 10x³y + 25y²

Therefore, the result of (x³ + 5y)(x³ + 5y) is x^6 + 10x³y + 25y².