Question

Решите уравнение: 1)2sinx=0; | 2) †cosx=0; | 3)cosx-1=0; | 4)1-sinx=0. нужен полный ответ помогите пожалуйста ​

Answer 1

Ответ:

535666х0364674-37373646464-7363636364-37374747474=63663✓

Объяснение:

Answer 2

1. 2sin(x) = 0

To solve this equation, we need to find the values of x that satisfy the equation.

We can rewrite the equation as sin(x) = 0/2, which simplifies to sin(x) = 0.

The solutions to this equation are the x-values where the sine function equals zero.

The sine function equals zero at x = 0, π, 2π, 3π, and so on.

Therefore, the solutions to the equation 2sin(x) = 0 are: x = 0 + kπ, where k is an integer.

2. †cos(x) = 0

I'm sorry, but I'm not sure what the symbol "†" represents in this context. Could you please clarify?

3. cos(x) - 1 = 0

To solve this equation, we want to find the values of x that satisfy the equation.

We can rearrange the equation as cos(x) = 1.

The cosine function equals 1 at x = 0, 2π, 4π, and so on.

Therefore, the solutions to the equation cos(x) - 1 = 0 are: x = 2kπ, where k is an integer.

4. 1 - sin(x) = 0

To solve this equation, we want to find the values of x that satisfy the equation.

We can rearrange the equation as sin(x) = 1.

The sine function equals 1 at x = π/2, 5π/2, 9π/2, and so on.

Therefore, the solutions to the equation 1 - sin(x) = 0 are: x = π/2 + 2kπ, where k is an integer.

I hope this helps! Let me know if you have any further questions.