Question

Log7(2x-6)=log7(x+1)

Answer 1

$log_7(2x-6)=log_7(x+1)\; ,\; \; ODZ:\; x>3\\\\2x-6=x+1\\\\x=7>3\\\\Otvet:\; \; x=7.$

Answer 2

Log7(2x-6)=log7(x+1)

ОДЗ  2х-6>0  x>3

         x+1>0   x>-1

так как основания логарифмов одинаковы имеем право записать

2х-6= х+1

х=7

Answer 3

To solve the equation log₇(2x - 6) = log₇(x + 1), we can start by using the property of logarithms that states: logₐ(b) = logₐ(c) if and only if b = c.

Using this property, we can equate the expressions inside the logarithms:

2x - 6 = x + 1

Now, we can solve for x. Let's simplify the equation:

2x - x = 1 + 6 x = 7

Therefore, the solution to the equation log₇(2x - 6) = log₇(x + 1) is x = 7.